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1061448307 is a prime number
BaseRepresentation
bin111111010001000…
…110101001110011
32201222022011100021
4333101012221303
54133212321212
6253154304311
735206106323
oct7721065163
92658264307
101061448307
114a5183907
12257588097
1313bba342a
14a0d85283
15632bd307
hex3f446a73

1061448307 has 2 divisors, whose sum is σ = 1061448308. Its totient is φ = 1061448306.

The previous prime is 1061448299. The next prime is 1061448313. The reversal of 1061448307 is 7038441601.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1061448307 - 23 = 1061448299 is a prime.

It is a super-2 number, since 2×10614483072 = 2253345016866332498, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1061448317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 530724153 + 530724154.

It is an arithmetic number, because the mean of its divisors is an integer number (530724154).

Almost surely, 21061448307 is an apocalyptic number.

1061448307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1061448307 is an equidigital number, since it uses as much as digits as its factorization.

1061448307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 34.

The square root of 1061448307 is about 32579.8757977989. The cubic root of 1061448307 is about 1020.0769860513.

Adding to 1061448307 its reverse (7038441601), we get a palindrome (8099889908).

The spelling of 1061448307 in words is "one billion, sixty-one million, four hundred forty-eight thousand, three hundred seven".