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10633524752117 is a prime number
BaseRepresentation
bin1001101010111100111101…
…1101110010111011110101
31101122112222121211011121102
42122233033131302323311
52343204424314031432
634340550203055445
72145150441031361
oct232571735627365
941575877734542
1010633524752117
11342a71a564023
121238a21b11585
135c19774a2857
1428a9459c02a1
15136908085962
hex9abcf772ef5

10633524752117 has 2 divisors, whose sum is σ = 10633524752118. Its totient is φ = 10633524752116.

The previous prime is 10633524752111. The next prime is 10633524752167. The reversal of 10633524752117 is 71125742533601.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10054930244401 + 578594507716 = 3170951^2 + 760654^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10633524752117 is a prime.

It is a super-2 number, since 2×106335247521172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10633524752111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5316762376058 + 5316762376059.

It is an arithmetic number, because the mean of its divisors is an integer number (5316762376059).

Almost surely, 210633524752117 is an apocalyptic number.

It is an amenable number.

10633524752117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10633524752117 is an equidigital number, since it uses as much as digits as its factorization.

10633524752117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1058400, while the sum is 47.

The spelling of 10633524752117 in words is "ten trillion, six hundred thirty-three billion, five hundred twenty-four million, seven hundred fifty-two thousand, one hundred seventeen".