10642633034141 has 2 divisors, whose sum is σ = 10642633034142. Its totient is φ = 10642633034140.

The previous prime is 10642633034129. The next prime is 10642633034207. The reversal of 10642633034141 is 14143033624601.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10285997138041 + 356635896100 = 3207179^2 + 597190^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10642633034141 is a prime.

It is a super-3 number, since 3×10642633034141³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 10642633034095 and 10642633034104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10642633034101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5321316517070 + 5321316517071.

It is an arithmetic number, because the mean of its divisors is an integer number (5321316517071).

Almost surely, 2^{10642633034141} is an apocalyptic number.

It is an amenable number.

10642633034141 is a deficient number, since it is larger than the sum of its proper divisors (1).

10642633034141 is an equidigital number, since it uses as much as digits as its factorization.

10642633034141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 38.

Adding to 10642633034141 its reverse (14143033624601), we get a palindrome (24785666658742).

The spelling of 10642633034141 in words is "ten trillion, six hundred forty-two billion, six hundred thirty-three million, thirty-four thousand, one hundred forty-one".