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106433021403311 is a prime number
BaseRepresentation
bin11000001100110011011110…
…011011101110000010101111
3111221211220020021000112201012
4120030303132123232002233
5102422244311434401221
61014210353253135435
731263350326641341
oct3014633633560257
9457756207015635
10106433021403311
1130a04a99973a89
12bb2b52362a57b
13475078b145775
141c3d5585c7291
15c4887914a65b
hex60ccde6ee0af

106433021403311 has 2 divisors, whose sum is σ = 106433021403312. Its totient is φ = 106433021403310.

The previous prime is 106433021403281. The next prime is 106433021403337. The reversal of 106433021403311 is 113304120334601.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-106433021403311 is a prime.

It is a super-2 number, since 2×1064330214033112 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (106433021433311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53216510701655 + 53216510701656.

It is an arithmetic number, because the mean of its divisors is an integer number (53216510701656).

Almost surely, 2106433021403311 is an apocalyptic number.

106433021403311 is a deficient number, since it is larger than the sum of its proper divisors (1).

106433021403311 is an equidigital number, since it uses as much as digits as its factorization.

106433021403311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 106433021403311 its reverse (113304120334601), we get a palindrome (219737141737912).

The spelling of 106433021403311 in words is "one hundred six trillion, four hundred thirty-three billion, twenty-one million, four hundred three thousand, three hundred eleven".