Base | Representation |
---|---|
bin | 1001101011100001011010… |
… | …1110110111100001110111 |
3 | 1101200111020121010202111221 |
4 | 2122320112232313201313 |
5 | 2343334444422004221 |
6 | 34345245210211211 |
7 | 2145645103140601 |
oct | 232702656674167 |
9 | 41614217122457 |
10 | 10643310344311 |
11 | 34338912452a7 |
12 | 123a8b3123b07 |
13 | 5c287692caa8 |
14 | 28b1d3490171 |
15 | 136ccc1e0541 |
hex | 9ae16bb7877 |
10643310344311 has 2 divisors, whose sum is σ = 10643310344312. Its totient is φ = 10643310344310.
The previous prime is 10643310344273. The next prime is 10643310344347. The reversal of 10643310344311 is 11344301334601.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10643310344311 - 211 = 10643310342263 is a prime.
It is a super-2 number, since 2×106433103443112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10643310344351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5321655172155 + 5321655172156.
It is an arithmetic number, because the mean of its divisors is an integer number (5321655172156).
Almost surely, 210643310344311 is an apocalyptic number.
10643310344311 is a deficient number, since it is larger than the sum of its proper divisors (1).
10643310344311 is an equidigital number, since it uses as much as digits as its factorization.
10643310344311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 10643310344311 its reverse (11344301334601), we get a palindrome (21987611678912).
The spelling of 10643310344311 in words is "ten trillion, six hundred forty-three billion, three hundred ten million, three hundred forty-four thousand, three hundred eleven".
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