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106512016465277 is a prime number
BaseRepresentation
bin11000001101111101000010…
…111001111101110101111101
3111222010110010120011110212222
4120031331002321331311331
5102430043102203342102
61014310540031335125
731302145026614423
oct3015750271756575
9458113116143788
10106512016465277
1130a35546594265
12bb428aa9814a5
13475806a001897
141c432cdacb113
15c4a94e2aeaa2
hex60df42e7dd7d

106512016465277 has 2 divisors, whose sum is σ = 106512016465278. Its totient is φ = 106512016465276.

The previous prime is 106512016465243. The next prime is 106512016465367. The reversal of 106512016465277 is 772564610215601.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 64793580906916 + 41718435558361 = 8049446^2 + 6458981^2 .

It is a cyclic number.

It is not a de Polignac number, because 106512016465277 - 28 = 106512016465021 is a prime.

It is a super-2 number, since 2×1065120164652772 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (106512016465577) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53256008232638 + 53256008232639.

It is an arithmetic number, because the mean of its divisors is an integer number (53256008232639).

Almost surely, 2106512016465277 is an apocalyptic number.

It is an amenable number.

106512016465277 is a deficient number, since it is larger than the sum of its proper divisors (1).

106512016465277 is an equidigital number, since it uses as much as digits as its factorization.

106512016465277 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4233600, while the sum is 53.

The spelling of 106512016465277 in words is "one hundred six trillion, five hundred twelve billion, sixteen million, four hundred sixty-five thousand, two hundred seventy-seven".