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1067275351319 is a prime number
BaseRepresentation
bin11111000011111101001…
…00010111010100010111
310210000211020212101000112
433201332210113110113
5114441234442220234
62134144410433235
7140052035542352
oct17417644272427
93700736771015
101067275351319
113816a11260a1
12152a1843281b
137984a0a9428
1439929251299
151cb67a73ace
hexf87e917517

1067275351319 has 2 divisors, whose sum is σ = 1067275351320. Its totient is φ = 1067275351318.

The previous prime is 1067275351313. The next prime is 1067275351321. The reversal of 1067275351319 is 9131535727601.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1067275351319 - 236 = 998555874583 is a prime.

It is a super-2 number, since 2×10672753513192 (a number of 25 digits) contains 22 as substring.

Together with 1067275351321, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1067275351313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 533637675659 + 533637675660.

It is an arithmetic number, because the mean of its divisors is an integer number (533637675660).

Almost surely, 21067275351319 is an apocalyptic number.

1067275351319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1067275351319 is an equidigital number, since it uses as much as digits as its factorization.

1067275351319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1190700, while the sum is 50.

The spelling of 1067275351319 in words is "one trillion, sixty-seven billion, two hundred seventy-five million, three hundred fifty-one thousand, three hundred nineteen".