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1068134445533 is a prime number
BaseRepresentation
bin11111000101100011100…
…01100011000111011101
310210010001010101212201202
433202301301203013131
5120000014404224113
62134405540045245
7140112236661251
oct17426161430735
93703033355652
101068134445533
11381aa2059311
12153018093825
137995607cbbc
14399ab3a0261
151cbb81c0258
hexf8b1c631dd

1068134445533 has 2 divisors, whose sum is σ = 1068134445534. Its totient is φ = 1068134445532.

The previous prime is 1068134445493. The next prime is 1068134445551. The reversal of 1068134445533 is 3355444318601.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 752691586084 + 315442859449 = 867578^2 + 561643^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1068134445533 is a prime.

It is a super-2 number, since 2×10681344455332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1068134345533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 534067222766 + 534067222767.

It is an arithmetic number, because the mean of its divisors is an integer number (534067222767).

Almost surely, 21068134445533 is an apocalyptic number.

It is an amenable number.

1068134445533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1068134445533 is an equidigital number, since it uses as much as digits as its factorization.

1068134445533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2073600, while the sum is 47.

The spelling of 1068134445533 in words is "one trillion, sixty-eight billion, one hundred thirty-four million, four hundred forty-five thousand, five hundred thirty-three".