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1075351316213 is a prime number
BaseRepresentation
bin11111010010111111110…
…11101110011011110101
310210210200002012220011102
433221133323232123311
5120104304414104323
62142002022415445
7140456131241456
oct17513773563365
93723602186142
101075351316213
11385065869049
121544b0b91585
137a536299095
143a093a5112d
151ce8ba77328
hexfa5feee6f5

1075351316213 has 2 divisors, whose sum is σ = 1075351316214. Its totient is φ = 1075351316212.

The previous prime is 1075351316197. The next prime is 1075351316227. The reversal of 1075351316213 is 3126131535701.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 561574880689 + 513776435524 = 749383^2 + 716782^2 .

It is an emirp because it is prime and its reverse (3126131535701) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1075351316213 - 24 = 1075351316197 is a prime.

It is a super-2 number, since 2×10753513162132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1075351316113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 537675658106 + 537675658107.

It is an arithmetic number, because the mean of its divisors is an integer number (537675658107).

Almost surely, 21075351316213 is an apocalyptic number.

It is an amenable number.

1075351316213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1075351316213 is an equidigital number, since it uses as much as digits as its factorization.

1075351316213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56700, while the sum is 38.

The spelling of 1075351316213 in words is "one trillion, seventy-five billion, three hundred fifty-one million, three hundred sixteen thousand, two hundred thirteen".