10914433 has 2 divisors, whose sum is σ = 10914434. Its totient is φ = 10914432.

The previous prime is 10914427. The next prime is 10914457. The reversal of 10914433 is 33441901.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10909809 + 4624 = 3303^2 + 68^2 .

It is a cyclic number.

It is not a de Polignac number, because 10914433 - 2⁵ = 10914401 is a prime.

It is a super-2 number, since 2×10914433² = 238249695422978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10914398 and 10914407.

It is not a weakly prime, because it can be changed into another prime (10914133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5457216 + 5457217.

It is an arithmetic number, because the mean of its divisors is an integer number (5457217).

Almost surely, 2^10914433 is an apocalyptic number.

It is an amenable number.

10914433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10914433 is an equidigital number, since it uses as much as digits as its factorization.

10914433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

The square root of 10914433 is about 3303.6998955716. The cubic root of 10914433 is about 221.8198427463.

The spelling of 10914433 in words is "ten million, nine hundred fourteen thousand, four hundred thirty-three".