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109483400447 is a prime number
BaseRepresentation
bin110010111110110111…
…0000001110011111111
3101110121002100000000022
41211331232001303333
53243210222303242
6122143533122355
710624046356211
oct1457556016377
9343532300008
10109483400447
1142482586233
12192759293bb
13a42a4823b5
14542874a5b1
152cabaa10d2
hex197db81cff

109483400447 has 2 divisors, whose sum is σ = 109483400448. Its totient is φ = 109483400446.

The previous prime is 109483400437. The next prime is 109483400449. The reversal of 109483400447 is 744004384901.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-109483400447 is a prime.

It is a super-2 number, since 2×1094834004472 (a number of 23 digits) contains 22 as substring.

Together with 109483400449, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 109483400398 and 109483400407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (109483400449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54741700223 + 54741700224.

It is an arithmetic number, because the mean of its divisors is an integer number (54741700224).

Almost surely, 2109483400447 is an apocalyptic number.

109483400447 is a deficient number, since it is larger than the sum of its proper divisors (1).

109483400447 is an equidigital number, since it uses as much as digits as its factorization.

109483400447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 387072, while the sum is 44.

The spelling of 109483400447 in words is "one hundred nine billion, four hundred eighty-three million, four hundred thousand, four hundred forty-seven".