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109693321221053 is a prime number
BaseRepresentation
bin11000111100001111110111…
…011100100001001110111101
3112101101120122011022122000202
4120330033313130201032331
5103334203410213033203
61025144225513133245
732051036521100363
oct3074176734411675
9471346564278022
10109693321221053
1131a51749148479
12103773733ba225
13492906088785b
141d13283bbb633
15ca3595a3b388
hex63c3f77213bd

109693321221053 has 2 divisors, whose sum is σ = 109693321221054. Its totient is φ = 109693321221052.

The previous prime is 109693321221041. The next prime is 109693321221061. The reversal of 109693321221053 is 350122123396901.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81434507147449 + 28258814073604 = 9024107^2 + 5315902^2 .

It is a cyclic number.

It is not a de Polignac number, because 109693321221053 - 218 = 109693320958909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 109693321220989 and 109693321221007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (109693321221073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54846660610526 + 54846660610527.

It is an arithmetic number, because the mean of its divisors is an integer number (54846660610527).

Almost surely, 2109693321221053 is an apocalyptic number.

It is an amenable number.

109693321221053 is a deficient number, since it is larger than the sum of its proper divisors (1).

109693321221053 is an equidigital number, since it uses as much as digits as its factorization.

109693321221053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 524880, while the sum is 47.

The spelling of 109693321221053 in words is "one hundred nine trillion, six hundred ninety-three billion, three hundred twenty-one million, two hundred twenty-one thousand, fifty-three".