Base | Representation |
---|---|
bin | 110011001001101000… |
… | …1011011001001100011 |
3 | 101111112021202012110002 |
4 | 1212103101123021203 |
5 | 3244430310011203 |
6 | 122243451330215 |
7 | 10636030046516 |
oct | 1462321331143 |
9 | 344467665402 |
10 | 109845000803 |
11 | 426487039aa |
12 | 19356a5096b |
13 | a48736a6c5 |
14 | 5460796d7d |
15 | 2ccd6cbd88 |
hex | 199345b263 |
109845000803 has 2 divisors, whose sum is σ = 109845000804. Its totient is φ = 109845000802.
The previous prime is 109845000791. The next prime is 109845000841. The reversal of 109845000803 is 308000548901.
It is an a-pointer prime, because the next prime (109845000841) can be obtained adding 109845000803 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 109845000803 - 24 = 109845000787 is a prime.
It is a super-2 number, since 2×1098450008032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (109845000203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54922500401 + 54922500402.
It is an arithmetic number, because the mean of its divisors is an integer number (54922500402).
Almost surely, 2109845000803 is an apocalyptic number.
109845000803 is a deficient number, since it is larger than the sum of its proper divisors (1).
109845000803 is an equidigital number, since it uses as much as digits as its factorization.
109845000803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 38.
The spelling of 109845000803 in words is "one hundred nine billion, eight hundred forty-five million, eight hundred three", and thus it is an aban number.
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