Base | Representation |
---|---|
bin | 1001111111101001011001… |
… | …0100111110100101000011 |
3 | 1102220112122200100000101001 |
4 | 2133322112110332211003 |
5 | 2420021032344043041 |
6 | 35212144341152431 |
7 | 2212634602264504 |
oct | 237722624764503 |
9 | 42815580300331 |
10 | 10989048424771 |
11 | 355747a39639a |
12 | 12959020bb717 |
13 | 619355552b21 |
14 | 29dc30cacbab |
15 | 140cb4ed3131 |
hex | 9fe9653e943 |
10989048424771 has 2 divisors, whose sum is σ = 10989048424772. Its totient is φ = 10989048424770.
The previous prime is 10989048424769. The next prime is 10989048424807. The reversal of 10989048424771 is 17742484098901.
It is a weak prime.
It is an emirp because it is prime and its reverse (17742484098901) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10989048424771 - 21 = 10989048424769 is a prime.
Together with 10989048424769, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10989048424171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5494524212385 + 5494524212386.
It is an arithmetic number, because the mean of its divisors is an integer number (5494524212386).
Almost surely, 210989048424771 is an apocalyptic number.
10989048424771 is a deficient number, since it is larger than the sum of its proper divisors (1).
10989048424771 is an equidigital number, since it uses as much as digits as its factorization.
10989048424771 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32514048, while the sum is 64.
The spelling of 10989048424771 in words is "ten trillion, nine hundred eighty-nine billion, forty-eight million, four hundred twenty-four thousand, seven hundred seventy-one".
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