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109910499483133 is a prime number
BaseRepresentation
bin11000111111011010001000…
…010001110101110111111101
3112102011100012200112110001001
4120333122020101311313331
5103401233200331430013
61025432104133050301
732102525431625206
oct3077321021656775
9472140180473031
10109910499483133
1132025865663188
12103b1483a86991
134943691ab2c3b
141d1d9a75025ad
15ca905714addd
hex63f688475dfd

109910499483133 has 2 divisors, whose sum is σ = 109910499483134. Its totient is φ = 109910499483132.

The previous prime is 109910499483121. The next prime is 109910499483139. The reversal of 109910499483133 is 331384994019901.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97158615606649 + 12751883876484 = 9856907^2 + 3570978^2 .

It is a cyclic number.

It is not a de Polignac number, because 109910499483133 - 217 = 109910499352061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (109910499483139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54955249741566 + 54955249741567.

It is an arithmetic number, because the mean of its divisors is an integer number (54955249741567).

Almost surely, 2109910499483133 is an apocalyptic number.

It is an amenable number.

109910499483133 is a deficient number, since it is larger than the sum of its proper divisors (1).

109910499483133 is an equidigital number, since it uses as much as digits as its factorization.

109910499483133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22674816, while the sum is 64.

The spelling of 109910499483133 in words is "one hundred nine trillion, nine hundred ten billion, four hundred ninety-nine million, four hundred eighty-three thousand, one hundred thirty-three".