Base | Representation |
---|---|
bin | 1010000000010010010001… |
… | …1010010010011000111111 |
3 | 1102221120222110021021121221 |
4 | 2200010210122102120333 |
5 | 2420211021130202103 |
6 | 35221201305334211 |
7 | 2213503542154222 |
oct | 240044432223077 |
9 | 42846873237557 |
10 | 11000022115903 |
11 | 35610a0794a17 |
12 | 1297a65197367 |
13 | 61a3b3b985a2 |
14 | 2a05924915b9 |
15 | 1412085c71bd |
hex | a012469263f |
11000022115903 has 2 divisors, whose sum is σ = 11000022115904. Its totient is φ = 11000022115902.
The previous prime is 11000022115897. The next prime is 11000022115933. The reversal of 11000022115903 is 30951122000011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000022115903 - 241 = 8800998860351 is a prime.
It is a super-2 number, since 2×110000221159032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000022115933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500011057951 + 5500011057952.
It is an arithmetic number, because the mean of its divisors is an integer number (5500011057952).
Almost surely, 211000022115903 is an apocalyptic number.
11000022115903 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000022115903 is an equidigital number, since it uses as much as digits as its factorization.
11000022115903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 25.
Adding to 11000022115903 its reverse (30951122000011), we get a palindrome (41951144115914).
The spelling of 11000022115903 in words is "eleven trillion, twenty-two million, one hundred fifteen thousand, nine hundred three".
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