Base | Representation |
---|---|
bin | 10000000000011101101… |
… | …101001011010101111111 |
3 | 10220011022120220022211212 |
4 | 100000131231023111333 |
5 | 121010310030304413 |
6 | 2201200532035035 |
7 | 142321162545113 |
oct | 20003555132577 |
9 | 3804276808755 |
10 | 1100010009983 |
11 | 394569a78705 |
12 | 159233162a7b |
13 | 7c965ba1541 |
14 | 3b352951743 |
15 | 1d9317cbca8 |
hex | 1001db4b57f |
1100010009983 has 2 divisors, whose sum is σ = 1100010009984. Its totient is φ = 1100010009982.
The previous prime is 1100010009949. The next prime is 1100010010069. The reversal of 1100010009983 is 3899000100011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100010009983 - 26 = 1100010009919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100010009913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005004991 + 550005004992.
It is an arithmetic number, because the mean of its divisors is an integer number (550005004992).
Almost surely, 21100010009983 is an apocalyptic number.
1100010009983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100010009983 is an equidigital number, since it uses as much as digits as its factorization.
1100010009983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 32.
Adding to 1100010009983 its reverse (3899000100011), we get a palindrome (4999010109994).
The spelling of 1100010009983 in words is "one trillion, one hundred billion, ten million, nine thousand, nine hundred eighty-three".
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