11000100109993 has 2 divisors, whose sum is σ = 11000100109994. Its totient is φ = 11000100109992.

The previous prime is 11000100109991. The next prime is 11000100110029. The reversal of 11000100109993 is 39990100100011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6167260659609 + 4832839450384 = 2483397^2 + 2198372^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000100109993 - 2¹ = 11000100109991 is a prime.

Together with 11000100109991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11000100109991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050054996 + 5500050054997.

It is an arithmetic number, because the mean of its divisors is an integer number (5500050054997).

Almost surely, 2^{11000100109993} is an apocalyptic number.

It is an amenable number.

11000100109993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000100109993 is an equidigital number, since it uses as much as digits as its factorization.

11000100109993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2187, while the sum is 34.

The spelling of 11000100109993 in words is "eleven trillion, one hundred million, one hundred nine thousand, nine hundred ninety-three".