Base | Representation |
---|---|
bin | 10000000000011101101… |
… | …101100001010100100011 |
3 | 10220011022121001220022221 |
4 | 100000131231201110203 |
5 | 121010310041200003 |
6 | 2201200534011511 |
7 | 142321163401423 |
oct | 20003555412443 |
9 | 3804277056287 |
10 | 1100010100003 |
11 | 39456a02a301 |
12 | 1592331a6b97 |
13 | 7c965c034c9 |
14 | 3b352976483 |
15 | 1d9317e87bd |
hex | 1001db61523 |
1100010100003 has 2 divisors, whose sum is σ = 1100010100004. Its totient is φ = 1100010100002.
The previous prime is 1100010099989. The next prime is 1100010100043. The reversal of 1100010100003 is 3000010100011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100010100003 - 25 = 1100010099971 is a prime.
It is a super-2 number, since 2×11000101000032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100010100043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005050001 + 550005050002.
It is an arithmetic number, because the mean of its divisors is an integer number (550005050002).
Almost surely, 21100010100003 is an apocalyptic number.
1100010100003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100010100003 is an equidigital number, since it uses as much as digits as its factorization.
1100010100003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 7.
Adding to 1100010100003 its reverse (3000010100011), we get a palindrome (4100020200014).
The spelling of 1100010100003 in words is "one trillion, one hundred billion, ten million, one hundred thousand, three".
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