110001010999853 has 2 divisors, whose sum is σ = 110001010999854. Its totient is φ = 110001010999852.

The previous prime is 110001010999849. The next prime is 110001010999871. The reversal of 110001010999853 is 358999010100011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98298440506249 + 11702570493604 = 9914557^2 + 3420902^2 .

It is an emirp because it is prime and its reverse (358999010100011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110001010999853 - 2² = 110001010999849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110001010999798 and 110001010999807.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110001010999753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000505499926 + 55000505499927.

It is an arithmetic number, because the mean of its divisors is an integer number (55000505499927).

Almost surely, 2^{110001010999853} is an apocalyptic number.

It is an amenable number.

110001010999853 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001010999853 is an equidigital number, since it uses as much as digits as its factorization.

110001010999853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 87480, while the sum is 47.

The spelling of 110001010999853 in words is "one hundred ten trillion, one billion, ten million, nine hundred ninety-nine thousand, eight hundred fifty-three".