Base | Representation |
---|---|
bin | 11001000000101110011011… |
… | …110110010011100000100110 |
3 | 112102110222212100211221221021 |
4 | 121000232123312103200212 |
5 | 103404224043130401042 |
6 | 1025541434423241354 |
7 | 32112211605435253 |
oct | 3100563366234046 |
9 | 472428770757837 |
10 | 110001022122022 |
11 | 320601982a3639 |
12 | 10406b278a925a |
13 | 494c089c858a5 |
14 | 1d241139aa42a |
15 | cab5a4313867 |
hex | 640b9bd93826 |
110001022122022 has 4 divisors (see below), whose sum is σ = 165001533183036. Its totient is φ = 55000511061010.
The previous prime is 110001022122007. The next prime is 110001022122077. The reversal of 110001022122022 is 220221220100011.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 110001022121987 and 110001022122005.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500255530504 + ... + 27500255530507.
It is an arithmetic number, because the mean of its divisors is an integer number (41250383295759).
Almost surely, 2110001022122022 is an apocalyptic number.
110001022122022 is a deficient number, since it is larger than the sum of its proper divisors (55000511061014).
110001022122022 is an equidigital number, since it uses as much as digits as its factorization.
110001022122022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55000511061013.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 110001022122022 its reverse (220221220100011), we get a palindrome (330222242222033).
The spelling of 110001022122022 in words is "one hundred ten trillion, one billion, twenty-two million, one hundred twenty-two thousand, twenty-two".
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