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110001022122022 = 255000511061011
BaseRepresentation
bin11001000000101110011011…
…110110010011100000100110
3112102110222212100211221221021
4121000232123312103200212
5103404224043130401042
61025541434423241354
732112211605435253
oct3100563366234046
9472428770757837
10110001022122022
11320601982a3639
1210406b278a925a
13494c089c858a5
141d241139aa42a
15cab5a4313867
hex640b9bd93826

110001022122022 has 4 divisors (see below), whose sum is σ = 165001533183036. Its totient is φ = 55000511061010.

The previous prime is 110001022122007. The next prime is 110001022122077. The reversal of 110001022122022 is 220221220100011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 110001022121987 and 110001022122005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500255530504 + ... + 27500255530507.

It is an arithmetic number, because the mean of its divisors is an integer number (41250383295759).

Almost surely, 2110001022122022 is an apocalyptic number.

110001022122022 is a deficient number, since it is larger than the sum of its proper divisors (55000511061014).

110001022122022 is an equidigital number, since it uses as much as digits as its factorization.

110001022122022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55000511061013.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 110001022122022 its reverse (220221220100011), we get a palindrome (330222242222033).

The spelling of 110001022122022 in words is "one hundred ten trillion, one billion, twenty-two million, one hundred twenty-two thousand, twenty-two".

Divisors: 1 2 55000511061011 110001022122022