11000104481 has 2 divisors, whose sum is σ = 11000104482. Its totient is φ = 11000104480.

The previous prime is 11000104417. The next prime is 11000104501. The reversal of 11000104481 is 18440100011.

It is a happy number.

It is an a-pointer prime, because the next prime (11000104501) can be obtained adding 11000104481 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8393491456 + 2606613025 = 91616^2 + 51055^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000104481 - 2⁶ = 11000104417 is a prime.

It is a super-2 number, since 2×11000104481² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11000104681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500052240 + 5500052241.

It is an arithmetic number, because the mean of its divisors is an integer number (5500052241).

Almost surely, 2^11000104481 is an apocalyptic number.

It is an amenable number.

11000104481 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000104481 is an equidigital number, since it uses as much as digits as its factorization.

11000104481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 11000104481 its reverse (18440100011), we get a palindrome (29440204492).

The spelling of 11000104481 in words is "eleven billion, one hundred four thousand, four hundred eighty-one".