110001100000109 has 2 divisors, whose sum is σ = 110001100000110. Its totient is φ = 110001100000108.

The previous prime is 110001100000091. The next prime is 110001100000177. The reversal of 110001100000109 is 901000001100011.

It is a happy number.

Together with previous prime (110001100000091) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108700537662025 + 1300562338084 = 10425955^2 + 1140422^2 .

It is an emirp because it is prime and its reverse (901000001100011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110001100000109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110001100000093 and 110001100000102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110001100000409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000550000054 + 55000550000055.

It is an arithmetic number, because the mean of its divisors is an integer number (55000550000055).

Almost surely, 2^{110001100000109} is an apocalyptic number.

It is an amenable number.

110001100000109 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001100000109 is an equidigital number, since it uses as much as digits as its factorization.

110001100000109 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 14.

The spelling of 110001100000109 in words is "one hundred ten trillion, one billion, one hundred million, one hundred nine", and thus it is an aban number.