Base | Representation |
---|---|
bin | 1010000000010010100110… |
… | …1001101010000101111111 |
3 | 1102221121012120200211210012 |
4 | 2200010221221222011333 |
5 | 2420211211131444411 |
6 | 35221214125533435 |
7 | 2213505660345146 |
oct | 240045151520577 |
9 | 42847176624705 |
10 | 11000110031231 |
11 | 3561136382012 |
12 | 1297a8a71427b |
13 | 61a3c916a6a9 |
14 | 2a05a001875d |
15 | 14121119118b |
hex | a0129a6a17f |
11000110031231 has 2 divisors, whose sum is σ = 11000110031232. Its totient is φ = 11000110031230.
The previous prime is 11000110031227. The next prime is 11000110031249. The reversal of 11000110031231 is 13213001100011.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (13213001100011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11000110031231 - 22 = 11000110031227 is a prime.
It is a super-2 number, since 2×110001100312312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000110061231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500055015615 + 5500055015616.
It is an arithmetic number, because the mean of its divisors is an integer number (5500055015616).
Almost surely, 211000110031231 is an apocalyptic number.
11000110031231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000110031231 is an equidigital number, since it uses as much as digits as its factorization.
11000110031231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 11000110031231 its reverse (13213001100011), we get a palindrome (24213111131242).
The spelling of 11000110031231 in words is "eleven trillion, one hundred ten million, thirty-one thousand, two hundred thirty-one".
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