Base | Representation |
---|---|
bin | 11001000000101110100001… |
… | …001001010110011110010111 |
3 | 112102111000002120002110221122 |
4 | 121000232201021112132113 |
5 | 103404224233404012413 |
6 | 1025541451320234155 |
7 | 32112214035051506 |
oct | 3100564111263627 |
9 | 472430076073848 |
10 | 110001111000983 |
11 | 32060233489724 |
12 | 10406b5160b95b |
13 | 494c0a25044a7 |
14 | 1d2412170483d |
15 | cab5ac01d108 |
hex | 640ba1256797 |
110001111000983 has 2 divisors, whose sum is σ = 110001111000984. Its totient is φ = 110001111000982.
The previous prime is 110001111000817. The next prime is 110001111001043. The reversal of 110001111000983 is 389000111100011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110001111000983 - 220 = 110001109952407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110001111008983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000555500491 + 55000555500492.
It is an arithmetic number, because the mean of its divisors is an integer number (55000555500492).
Almost surely, 2110001111000983 is an apocalyptic number.
110001111000983 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001111000983 is an equidigital number, since it uses as much as digits as its factorization.
110001111000983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 26.
Adding to 110001111000983 its reverse (389000111100011), we get a palindrome (499001222100994).
The spelling of 110001111000983 in words is "one hundred ten trillion, one billion, one hundred eleven million, nine hundred eighty-three", and thus it is an aban number.
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