Base | Representation |
---|---|
bin | 11001000000101110100001… |
… | …001001010110011111010011 |
3 | 112102111000002120002111000212 |
4 | 121000232201021112133103 |
5 | 103404224233404013133 |
6 | 1025541451320234335 |
7 | 32112214035051623 |
oct | 3100564111263723 |
9 | 472430076074025 |
10 | 110001111001043 |
11 | 32060233489779 |
12 | 10406b5160b9ab |
13 | 494c0a2504522 |
14 | 1d24121704883 |
15 | cab5ac01d148 |
hex | 640ba12567d3 |
110001111001043 has 2 divisors, whose sum is σ = 110001111001044. Its totient is φ = 110001111001042.
The previous prime is 110001111000983. The next prime is 110001111001057. The reversal of 110001111001043 is 340100111100011.
It is a happy number.
It is an a-pointer prime, because the next prime (110001111001057) can be obtained adding 110001111001043 to its sum of digits (14).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110001111001043 - 212 = 110001110996947 is a prime.
It is not a weakly prime, because it can be changed into another prime (110001111006043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000555500521 + 55000555500522.
It is an arithmetic number, because the mean of its divisors is an integer number (55000555500522).
Almost surely, 2110001111001043 is an apocalyptic number.
110001111001043 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001111001043 is an equidigital number, since it uses as much as digits as its factorization.
110001111001043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 110001111001043 its reverse (340100111100011), we get a palindrome (450101222101054).
The spelling of 110001111001043 in words is "one hundred ten trillion, one billion, one hundred eleven million, one thousand, forty-three".
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