Base | Representation |
---|---|
bin | 11001000000101110100111… |
… | …001110111100110110100101 |
3 | 112102111000100200021021122012 |
4 | 121000232213032330312211 |
5 | 103404224441030212242 |
6 | 1025541505405244005 |
7 | 32112216415131242 |
oct | 3100564716746645 |
9 | 472430320237565 |
10 | 110001213132197 |
11 | 320602860a6392 |
12 | 10406b7b863605 |
13 | 494c0ba71306a |
14 | 1d241310cc5c9 |
15 | cab5b5e94282 |
hex | 640ba73bcda5 |
110001213132197 has 2 divisors, whose sum is σ = 110001213132198. Its totient is φ = 110001213132196.
The previous prime is 110001213132103. The next prime is 110001213132281. The reversal of 110001213132197 is 791231312100011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 69122695768036 + 40878517364161 = 8314006^2 + 6393631^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110001213132197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110001213132497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000606566098 + 55000606566099.
It is an arithmetic number, because the mean of its divisors is an integer number (55000606566099).
Almost surely, 2110001213132197 is an apocalyptic number.
It is an amenable number.
110001213132197 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001213132197 is an equidigital number, since it uses as much as digits as its factorization.
110001213132197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2268, while the sum is 32.
The spelling of 110001213132197 in words is "one hundred ten trillion, one billion, two hundred thirteen million, one hundred thirty-two thousand, one hundred ninety-seven".
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