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110001213132197 is a prime number
BaseRepresentation
bin11001000000101110100111…
…001110111100110110100101
3112102111000100200021021122012
4121000232213032330312211
5103404224441030212242
61025541505405244005
732112216415131242
oct3100564716746645
9472430320237565
10110001213132197
11320602860a6392
1210406b7b863605
13494c0ba71306a
141d241310cc5c9
15cab5b5e94282
hex640ba73bcda5

110001213132197 has 2 divisors, whose sum is σ = 110001213132198. Its totient is φ = 110001213132196.

The previous prime is 110001213132103. The next prime is 110001213132281. The reversal of 110001213132197 is 791231312100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69122695768036 + 40878517364161 = 8314006^2 + 6393631^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110001213132197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110001213132497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000606566098 + 55000606566099.

It is an arithmetic number, because the mean of its divisors is an integer number (55000606566099).

Almost surely, 2110001213132197 is an apocalyptic number.

It is an amenable number.

110001213132197 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001213132197 is an equidigital number, since it uses as much as digits as its factorization.

110001213132197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2268, while the sum is 32.

The spelling of 110001213132197 in words is "one hundred ten trillion, one billion, two hundred thirteen million, one hundred thirty-two thousand, one hundred ninety-seven".