Base | Representation |
---|---|
bin | 11001000000101110100111… |
… | …101001100111010110100100 |
3 | 112102111000101011102101212112 |
4 | 121000232213221213112210 |
5 | 103404224444322401040 |
6 | 1025541510215140152 |
7 | 32112216531422603 |
oct | 3100564751472644 |
9 | 472430334371775 |
10 | 110001220122020 |
11 | 3206028a03a9a7 |
12 | 10406b82074658 |
13 | 494c0bbcbc756 |
14 | 1d24131dcba3a |
15 | cab5b68c5365 |
hex | 640ba7a675a4 |
110001220122020 has 24 divisors (see below), whose sum is σ = 231003854235000. Its totient is φ = 44000241957632.
The previous prime is 110001220121987. The next prime is 110001220122023. The reversal of 110001220122020 is 20221022100011.
It can be written as a sum of positive squares in 4 ways, for example, as 21877490766244 + 88123729355776 = 4677338^2 + 9387424^2 .
It is a junction number, because it is equal to n+sod(n) for n = 110001220121986 and 110001220122004.
It is not an unprimeable number, because it can be changed into a prime (110001220122023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11693795 + ... + 18887754.
It is an arithmetic number, because the mean of its divisors is an integer number (9625160593125).
Almost surely, 2110001220122020 is an apocalyptic number.
110001220122020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
110001220122020 is an abundant number, since it is smaller than the sum of its proper divisors (121002634112980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110001220122020 is a wasteful number, since it uses less digits than its factorization.
110001220122020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30761407 (or 30761405 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 110001220122020 its reverse (20221022100011), we get a palindrome (130222242222031).
The spelling of 110001220122020 in words is "one hundred ten trillion, one billion, two hundred twenty million, one hundred twenty-two thousand, twenty".
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