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110001253 is a prime number
BaseRepresentation
bin1101000111001…
…11110001100101
321122222122100111
412203213301211
5211130020003
614525413021
72503665235
oct643476145
9248878314
10110001253
115710262a
1230a0a171
1319a35acb
1410875cc5
1599cce6d
hex68e7c65

110001253 has 2 divisors, whose sum is σ = 110001254. Its totient is φ = 110001252.

The previous prime is 110001247. The next prime is 110001301. The reversal of 110001253 is 352100011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106151809 + 3849444 = 10303^2 + 1962^2 .

It is an emirp because it is prime and its reverse (352100011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110001253 - 217 = 109870181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110001053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000626 + 55000627.

It is an arithmetic number, because the mean of its divisors is an integer number (55000627).

Almost surely, 2110001253 is an apocalyptic number.

It is an amenable number.

110001253 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001253 is an equidigital number, since it uses as much as digits as its factorization.

110001253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 110001253 is about 10488.1482159626. The cubic root of 110001253 is about 479.1438049870.

Adding to 110001253 its reverse (352100011), we get a palindrome (462101264).

The spelling of 110001253 in words is "one hundred ten million, one thousand, two hundred fifty-three".