Base | Representation |
---|---|
bin | 10000000000011101111… |
… | …001110001100000010010 |
3 | 10220011022211010002101110 |
4 | 100000131321301200102 |
5 | 121010311401441033 |
6 | 2201201130514150 |
7 | 142321232610045 |
oct | 20003571614022 |
9 | 3804284102343 |
10 | 1100013312018 |
11 | 394570923565 |
12 | 159234295956 |
13 | 7c9667894ca |
14 | 3b353170c5c |
15 | 1d931c30363 |
hex | 1001de71812 |
1100013312018 has 32 divisors (see below), whose sum is σ = 2259710597376. Its totient is φ = 356725738368.
The previous prime is 1100013312017. The next prime is 1100013312019. The reversal of 1100013312018 is 8102133100011.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (1100013312017) and next prime (1100013312019).
It is a junction number, because it is equal to n+sod(n) for n = 1100013311985 and 1100013312003.
It is not an unprimeable number, because it can be changed into a prime (1100013312017) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2049255 + ... + 2529717.
It is an arithmetic number, because the mean of its divisors is an integer number (70615956168).
Almost surely, 21100013312018 is an apocalyptic number.
1100013312018 is an abundant number, since it is smaller than the sum of its proper divisors (1159697285358).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1100013312018 is a wasteful number, since it uses less digits than its factorization.
1100013312018 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 490818.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 1100013312018 its reverse (8102133100011), we get a palindrome (9202146412029).
The spelling of 1100013312018 in words is "one trillion, one hundred billion, thirteen million, three hundred twelve thousand, eighteen".
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