1100013312019 has 2 divisors, whose sum is σ = 1100013312020. Its totient is φ = 1100013312018.

The previous prime is 1100013312017. The next prime is 1100013312091. The reversal of 1100013312019 is 9102133100011.

Together with next prime (1100013312091) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1100013312019 - 2¹ = 1100013312017 is a prime.

It is a super-2 number, since 2×1100013312019² (a number of 25 digits) contains 22 as substring.

Together with 1100013312017, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1100013312017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006656009 + 550006656010.

It is an arithmetic number, because the mean of its divisors is an integer number (550006656010).

Almost surely, 2^{1100013312019} is an apocalyptic number.

1100013312019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100013312019 is an equidigital number, since it uses as much as digits as its factorization.

1100013312019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 22.

The spelling of 1100013312019 in words is "one trillion, one hundred billion, thirteen million, three hundred twelve thousand, nineteen".