1100013435432 has 24 divisors (see below), whose sum is σ = 2979203054490. Its totient is φ = 366671145120.

The previous prime is 1100013435431. The next prime is 1100013435463. The reversal of 1100013435432 is 2345343100011.

It is a happy number.

1100013435432 is a `hidden beast` number, since 1 + 100 + 0 + 13 + 4 + 3 + 543 + 2 = 666.

It can be written as a sum of positive squares in only one way, i.e., 856761276996 + 243252158436 = 925614^2 + 493206^2 .

It is a tau number, because it is divible by the number of its divisors (24).

It is a junction number, because it is equal to n+sod(n) for n = 1100013435396 and 1100013435405.

It is not an unprimeable number, because it can be changed into a prime (1100013435431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7638982119 + ... + 7638982262.

Almost surely, 2^{1100013435432} is an apocalyptic number.

1100013435432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1100013435432 is an abundant number, since it is smaller than the sum of its proper divisors (1879189619058).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1100013435432 is a wasteful number, since it uses less digits than its factorization.

1100013435432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15277964393 (or 15277964386 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 1100013435432 its reverse (2345343100011), we get a palindrome (3445356535443).

The spelling of 1100013435432 in words is "one trillion, one hundred billion, thirteen million, four hundred thirty-five thousand, four hundred thirty-two".