110002012020113 has 2 divisors, whose sum is σ = 110002012020114. Its totient is φ = 110002012020112.

The previous prime is 110002012020097. The next prime is 110002012020127. The reversal of 110002012020113 is 311020210200011.

It is an a-pointer prime, because the next prime (110002012020127) can be obtained adding 110002012020113 to its sum of digits (14).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80159915584849 + 29842096435264 = 8953207^2 + 5462792^2 .

It is a cyclic number.

It is not a de Polignac number, because 110002012020113 - 2⁴ = 110002012020097 is a prime.

It is not a weakly prime, because it can be changed into another prime (110002512020113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001006010056 + 55001006010057.

It is an arithmetic number, because the mean of its divisors is an integer number (55001006010057).

Almost surely, 2^{110002012020113} is an apocalyptic number.

It is an amenable number.

110002012020113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110002012020113 is an equidigital number, since it uses as much as digits as its factorization.

110002012020113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 110002012020113 its reverse (311020210200011), we get a palindrome (421022222220124).

The spelling of 110002012020113 in words is "one hundred ten trillion, two billion, twelve million, twenty thousand, one hundred thirteen".