Base | Representation |
---|---|
bin | 1010000000010010111110… |
… | …1111011100010101100001 |
3 | 1102221121110200222010010121 |
4 | 2200010233233130111201 |
5 | 2420211413311223131 |
6 | 35221232220000241 |
7 | 2213511341016364 |
oct | 240045757342541 |
9 | 42847420863117 |
10 | 11000212211041 |
11 | 3561189022239 |
12 | 1297ab8990081 |
13 | 61a414395411 |
14 | 2a05ad8160db |
15 | 14121a126911 |
hex | a012fbdc561 |
11000212211041 has 2 divisors, whose sum is σ = 11000212211042. Its totient is φ = 11000212211040.
The previous prime is 11000212210997. The next prime is 11000212211057. The reversal of 11000212211041 is 14011221200011.
It is an a-pointer prime, because the next prime (11000212211057) can be obtained adding 11000212211041 to its sum of digits (16).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10613944989025 + 386267222016 = 3257905^2 + 621504^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000212211041 - 221 = 11000210113889 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000212211441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500106105520 + 5500106105521.
It is an arithmetic number, because the mean of its divisors is an integer number (5500106105521).
Almost surely, 211000212211041 is an apocalyptic number.
It is an amenable number.
11000212211041 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000212211041 is an equidigital number, since it uses as much as digits as its factorization.
11000212211041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 11000212211041 its reverse (14011221200011), we get a palindrome (25011433411052).
The spelling of 11000212211041 in words is "eleven trillion, two hundred twelve million, two hundred eleven thousand, forty-one".
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