Base | Representation |
---|---|
bin | 10100011111010101… |
… | …00100010010001111 |
3 | 1001101121212211210201 |
4 | 22033222210102033 |
5 | 140012030011101 |
6 | 5015313114331 |
7 | 536411312263 |
oct | 121752442217 |
9 | 31347784721 |
10 | 11000235151 |
11 | 4735389534 |
12 | 216bb589a7 |
13 | 1063caa6a9 |
14 | 764d320a3 |
15 | 445ad8e01 |
hex | 28faa448f |
11000235151 has 2 divisors, whose sum is σ = 11000235152. Its totient is φ = 11000235150.
The previous prime is 11000235149. The next prime is 11000235167. The reversal of 11000235151 is 15153200011.
11000235151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (15153200011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11000235151 - 21 = 11000235149 is a prime.
Together with 11000235149, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000235121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500117575 + 5500117576.
It is an arithmetic number, because the mean of its divisors is an integer number (5500117576).
Almost surely, 211000235151 is an apocalyptic number.
11000235151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000235151 is an equidigital number, since it uses as much as digits as its factorization.
11000235151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 150, while the sum is 19.
Adding to 11000235151 its reverse (15153200011), we get a palindrome (26153435162).
The spelling of 11000235151 in words is "eleven billion, two hundred thirty-five thousand, one hundred fifty-one".
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