Base | Representation |
---|---|
bin | 10000000000011110111… |
… | …001100011110110111101 |
3 | 10220011100222120121201201 |
4 | 100000132321203312331 |
5 | 121010330142031331 |
6 | 2201202525135501 |
7 | 142321525002211 |
oct | 20003671436675 |
9 | 3804328517651 |
10 | 1100030033341 |
11 | 39457a304538 |
12 | 1592399ba591 |
13 | 7c96a092495 |
14 | 3b355484941 |
15 | 1d933434a61 |
hex | 1001ee63dbd |
1100030033341 has 2 divisors, whose sum is σ = 1100030033342. Its totient is φ = 1100030033340.
The previous prime is 1100030033339. The next prime is 1100030033359. The reversal of 1100030033341 is 1433300300011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1078785513316 + 21244520025 = 1038646^2 + 145755^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100030033341 - 21 = 1100030033339 is a prime.
Together with 1100030033339, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100030033381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550015016670 + 550015016671.
It is an arithmetic number, because the mean of its divisors is an integer number (550015016671).
Almost surely, 21100030033341 is an apocalyptic number.
It is an amenable number.
1100030033341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100030033341 is an equidigital number, since it uses as much as digits as its factorization.
1100030033341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 1100030033341 its reverse (1433300300011), we get a palindrome (2533330333352).
The spelling of 1100030033341 in words is "one trillion, one hundred billion, thirty million, thirty-three thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •