Base | Representation |
---|---|
bin | 10100011111010101… |
… | …10110101000101001 |
3 | 1001101122000122220111 |
4 | 22033222312220221 |
5 | 140012034412223 |
6 | 5015314454321 |
7 | 536412044356 |
oct | 121752665051 |
9 | 31348018814 |
10 | 11000310313 |
11 | 473542aa53 |
12 | 216bb943a1 |
13 | 1064005975 |
14 | 764d5162d |
15 | 445b0130d |
hex | 28fab6a29 |
11000310313 has 2 divisors, whose sum is σ = 11000310314. Its totient is φ = 11000310312.
The previous prime is 11000310311. The next prime is 11000310329. The reversal of 11000310313 is 31301300011.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8304312384 + 2695997929 = 91128^2 + 51923^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000310313 - 21 = 11000310311 is a prime.
It is a super-3 number, since 3×110003103133 (a number of 31 digits) contains 333 as substring.
Together with 11000310311, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 11000310293 and 11000310302.
It is not a weakly prime, because it can be changed into another prime (11000310311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500155156 + 5500155157.
It is an arithmetic number, because the mean of its divisors is an integer number (5500155157).
Almost surely, 211000310313 is an apocalyptic number.
It is an amenable number.
11000310313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000310313 is an equidigital number, since it uses as much as digits as its factorization.
11000310313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 13.
Adding to 11000310313 its reverse (31301300011), we get a palindrome (42301610324).
The spelling of 11000310313 in words is "eleven billion, three hundred ten thousand, three hundred thirteen".
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