11000311241 has 2 divisors, whose sum is σ = 11000311242. Its totient is φ = 11000311240.

The previous prime is 11000311199. The next prime is 11000311243. The reversal of 11000311241 is 14211300011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10877655616 + 122655625 = 104296^2 + 11075^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000311241 - 2¹⁸ = 11000049097 is a prime.

It is a super-3 number, since 3×11000311241³ (a number of 31 digits) contains 333 as substring.

Together with 11000311243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11000311243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500155620 + 5500155621.

It is an arithmetic number, because the mean of its divisors is an integer number (5500155621).

Almost surely, 2^11000311241 is an apocalyptic number.

It is an amenable number.

11000311241 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000311241 is an equidigital number, since it uses as much as digits as its factorization.

11000311241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11000311241 its reverse (14211300011), we get a palindrome (25211611252).

The spelling of 11000311241 in words is "eleven billion, three hundred eleven thousand, two hundred forty-one".