11000399 has 2 divisors, whose sum is σ = 11000400. Its totient is φ = 11000398.

The previous prime is 11000393. The next prime is 11000401. The reversal of 11000399 is 99300011.

It is a strong prime.

It is an emirp because it is prime and its reverse (99300011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000399 - 2⁴ = 11000383 is a prime.

Together with 11000401, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500199 + 5500200.

It is an arithmetic number, because the mean of its divisors is an integer number (5500200).

Almost surely, 2^11000399 is an apocalyptic number.

11000399 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000399 is an equidigital number, since it uses as much as digits as its factorization.

11000399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 23.

The square root of 11000399 is about 3316.6849413232. The cubic root of 11000399 is about 222.4006980185.

The spelling of 11000399 in words is "eleven million, three hundred ninety-nine", and thus it is an aban number.