Base | Representation |
---|---|
bin | 1010000000010011110001… |
… | …0101001100001110110110 |
3 | 1102221122000102102022101101 |
4 | 2200010330111030032312 |
5 | 2420212331344330032 |
6 | 35221305203120314 |
7 | 2213516514253303 |
oct | 240047425141666 |
9 | 42848012368341 |
10 | 11000423433142 |
11 | 356128727a560 |
12 | 1297b5767309a |
13 | 61a44907b600 |
14 | 2a05cd8ba0aa |
15 | 14122d94ade7 |
hex | a013c54c3b6 |
11000423433142 has 24 divisors (see below), whose sum is σ = 19491874556760. Its totient is φ = 4615562278080.
The previous prime is 11000423433133. The next prime is 11000423433149. The reversal of 11000423433142 is 24133432400011.
It is a happy number.
It is a self number, because there is not a number n which added to its sum of digits gives 11000423433142.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11000423433149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1479343167 + ... + 1479350602.
It is an arithmetic number, because the mean of its divisors is an integer number (812161439865).
Almost surely, 211000423433142 is an apocalyptic number.
11000423433142 is a deficient number, since it is larger than the sum of its proper divisors (8491451123618).
11000423433142 is a wasteful number, since it uses less digits than its factorization.
11000423433142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2958693808 (or 2958693795 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 11000423433142 its reverse (24133432400011), we get a palindrome (35133855833153).
The spelling of 11000423433142 in words is "eleven trillion, four hundred twenty-three million, four hundred thirty-three thousand, one hundred forty-two".
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