Base | Representation |
---|---|
bin | 110011001110011010… |
… | …0001101100100100101 |
3 | 101111221110000212001221 |
4 | 1212130310031210211 |
5 | 3300242302141143 |
6 | 122311411220341 |
7 | 10643013023332 |
oct | 1463464154445 |
9 | 344843025057 |
10 | 110005115173 |
11 | 42720024228 |
12 | 193a05a76b1 |
13 | a4b159b235 |
14 | 5477b55989 |
15 | 2cdc7a82ed |
hex | 199cd0d925 |
110005115173 has 2 divisors, whose sum is σ = 110005115174. Its totient is φ = 110005115172.
The previous prime is 110005115089. The next prime is 110005115189. The reversal of 110005115173 is 371511500011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105049236769 + 4955878404 = 324113^2 + 70398^2 .
It is an emirp because it is prime and its reverse (371511500011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110005115173 - 217 = 110004984101 is a prime.
It is a super-2 number, since 2×1100051151732 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110005115573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55002557586 + 55002557587.
It is an arithmetic number, because the mean of its divisors is an integer number (55002557587).
Almost surely, 2110005115173 is an apocalyptic number.
It is an amenable number.
110005115173 is a deficient number, since it is larger than the sum of its proper divisors (1).
110005115173 is an equidigital number, since it uses as much as digits as its factorization.
110005115173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 525, while the sum is 25.
Adding to 110005115173 its reverse (371511500011), we get a palindrome (481516615184).
The spelling of 110005115173 in words is "one hundred ten billion, five million, one hundred fifteen thousand, one hundred seventy-three".
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