Base | Representation |
---|---|
bin | 1010000000010101110101… |
… | …0100011011101000111111 |
3 | 1102221200102222211102211002 |
4 | 2200011131110123220333 |
5 | 2420220000040212424 |
6 | 35221440133320515 |
7 | 2213536314431441 |
oct | 240053524335077 |
9 | 42850388742732 |
10 | 11000976882239 |
11 | 3561540723003 |
12 | 1298090a9613b |
13 | 61a506928996 |
14 | 2a06431c6491 |
15 | 141262320cae |
hex | a015d51ba3f |
11000976882239 has 2 divisors, whose sum is σ = 11000976882240. Its totient is φ = 11000976882238.
The previous prime is 11000976882223. The next prime is 11000976882241. The reversal of 11000976882239 is 93228867900011.
11000976882239 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11000976882239 - 24 = 11000976882223 is a prime.
Together with 11000976882241, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000976842239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500488441119 + 5500488441120.
It is an arithmetic number, because the mean of its divisors is an integer number (5500488441120).
Almost surely, 211000976882239 is an apocalyptic number.
11000976882239 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000976882239 is an equidigital number, since it uses as much as digits as its factorization.
11000976882239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2612736, while the sum is 56.
The spelling of 11000976882239 in words is "eleven trillion, nine hundred seventy-six million, eight hundred eighty-two thousand, two hundred thirty-nine".
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