Base | Representation |
---|---|
bin | 10000000000100011000… |
… | …100011000000001111111 |
3 | 10220011112212012010212022 |
4 | 100000203010120001333 |
5 | 121011001043233333 |
6 | 2201213504230355 |
7 | 142323334343453 |
oct | 20004304300177 |
9 | 3804485163768 |
10 | 1100099977343 |
11 | 3946058374a4 |
12 | 15925930b3bb |
13 | 7c97b711673 |
14 | 3b360890663 |
15 | 1d93964dc98 |
hex | 1002311807f |
1100099977343 has 2 divisors, whose sum is σ = 1100099977344. Its totient is φ = 1100099977342.
The previous prime is 1100099977313. The next prime is 1100099977357. The reversal of 1100099977343 is 3437799900011.
It is a strong prime.
It is an emirp because it is prime and its reverse (3437799900011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1100099977343 - 28 = 1100099977087 is a prime.
It is a super-2 number, since 2×11000999773432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100099977313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550049988671 + 550049988672.
It is an arithmetic number, because the mean of its divisors is an integer number (550049988672).
Almost surely, 21100099977343 is an apocalyptic number.
1100099977343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100099977343 is an equidigital number, since it uses as much as digits as its factorization.
1100099977343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1285956, while the sum is 53.
The spelling of 1100099977343 in words is "one trillion, one hundred billion, ninety-nine million, nine hundred seventy-seven thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •