Base | Representation |
---|---|
bin | 10000000000100011000… |
… | …100011000100001001111 |
3 | 10220011112212012020121101 |
4 | 100000203010120201033 |
5 | 121011001043314333 |
6 | 2201213504243531 |
7 | 142323334352341 |
oct | 20004304304117 |
9 | 3804485166541 |
10 | 1100099979343 |
11 | 394605838a52 |
12 | 1592593105a7 |
13 | 7c97b712551 |
14 | 3b360891291 |
15 | 1d93964e67d |
hex | 1002311884f |
1100099979343 has 2 divisors, whose sum is σ = 1100099979344. Its totient is φ = 1100099979342.
The previous prime is 1100099979337. The next prime is 1100099979383. The reversal of 1100099979343 is 3439799900011.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (3439799900011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100099979343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100099979383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550049989671 + 550049989672.
It is an arithmetic number, because the mean of its divisors is an integer number (550049989672).
Almost surely, 21100099979343 is an apocalyptic number.
1100099979343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100099979343 is an equidigital number, since it uses as much as digits as its factorization.
1100099979343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1653372, while the sum is 55.
The spelling of 1100099979343 in words is "one trillion, one hundred billion, ninety-nine million, nine hundred seventy-nine thousand, three hundred forty-three".
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