Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …000010110001100000111100 |
3 | 112102111212001010120102222210 |
4 | 121000312303002301200330 |
5 | 103404400440301414322 |
6 | 1025545521420140420 |
7 | 32112650245363560 |
oct | 3100666302614074 |
9 | 472455033512883 |
10 | 110010001201212 |
11 | 32063a857a5742 |
12 | 10408812997710 |
13 | 494cb8b2bc5b8 |
14 | 1d247262d76a0 |
15 | cab92c75b70c |
hex | 640db30b183c |
110010001201212 has 96 divisors (see below), whose sum is σ = 299234687180800. Its totient is φ = 30806713333440.
The previous prime is 110010001201193. The next prime is 110010001201253. The reversal of 110010001201212 is 212102100010011.
It is a super-3 number, since 3×1100100012012123 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47992864 + ... + 50232807.
Almost surely, 2110010001201212 is an apocalyptic number.
110010001201212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
110010001201212 is an abundant number, since it is smaller than the sum of its proper divisors (189224685979588).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110010001201212 is a wasteful number, since it uses less digits than its factorization.
110010001201212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98225951 (or 98225949 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 12.
Adding to 110010001201212 its reverse (212102100010011), we get a palindrome (322112101211223).
The spelling of 110010001201212 in words is "one hundred ten trillion, ten billion, one million, two hundred one thousand, two hundred twelve".
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