Base | Representation |
---|---|
bin | 1010000000010101111010… |
… | …1101011101100101000001 |
3 | 1102221200111121202011120101 |
4 | 2200011132231131211001 |
5 | 2420220022024032433 |
6 | 35221442325442401 |
7 | 2213540020004446 |
oct | 240053655354501 |
9 | 42850447664511 |
10 | 11001000220993 |
11 | 3561552913832 |
12 | 1298098870401 |
13 | 61a50b70a9b3 |
14 | 2a064633d9cd |
15 | 1412643d107d |
hex | a015eb5d941 |
11001000220993 has 2 divisors, whose sum is σ = 11001000220994. Its totient is φ = 11001000220992.
The previous prime is 11001000220961. The next prime is 11001000221021. The reversal of 11001000220993 is 39902200010011.
It is an a-pointer prime, because the next prime (11001000221021) can be obtained adding 11001000220993 to its sum of digits (28).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10044158239504 + 956841981489 = 3169252^2 + 978183^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001000220993 - 25 = 11001000220961 is a prime.
It is not a weakly prime, because it can be changed into another prime (11001000220393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500500110496 + 5500500110497.
It is an arithmetic number, because the mean of its divisors is an integer number (5500500110497).
Almost surely, 211001000220993 is an apocalyptic number.
It is an amenable number.
11001000220993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001000220993 is an equidigital number, since it uses as much as digits as its factorization.
11001000220993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 28.
The spelling of 11001000220993 in words is "eleven trillion, one billion, two hundred twenty thousand, nine hundred ninety-three".
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