11001000253 has 2 divisors, whose sum is σ = 11001000254. Its totient is φ = 11001000252.

The previous prime is 11001000221. The next prime is 11001000317. The reversal of 11001000253 is 35200010011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5660606169 + 5340394084 = 75237^2 + 73078^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001000253 - 2⁵ = 11001000221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001000053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500500126 + 5500500127.

It is an arithmetic number, because the mean of its divisors is an integer number (5500500127).

Almost surely, 2^11001000253 is an apocalyptic number.

It is an amenable number.

11001000253 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001000253 is an equidigital number, since it uses as much as digits as its factorization.

11001000253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 13.

Adding to 11001000253 its reverse (35200010011), we get a palindrome (46201010264).

The spelling of 11001000253 in words is "eleven billion, one million, two hundred fifty-three", and thus it is an aban number.