Base | Representation |
---|---|
bin | 110011001110100011… |
… | …0111000100101111111 |
3 | 101111221210020112111012 |
4 | 1212131012320211333 |
5 | 3300300030304413 |
6 | 122312104145435 |
7 | 10643102441036 |
oct | 1463506704577 |
9 | 344853215435 |
10 | 110010009983 |
11 | 42722867825 |
12 | 193a216827b |
13 | a4b25c3183 |
14 | 547866b71d |
15 | 2cdce237a8 |
hex | 199d1b897f |
110010009983 has 2 divisors, whose sum is σ = 110010009984. Its totient is φ = 110010009982.
The previous prime is 110010009971. The next prime is 110010010001. The reversal of 110010009983 is 389900010011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110010009983 - 210 = 110010008959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110015009983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005004991 + 55005004992.
It is an arithmetic number, because the mean of its divisors is an integer number (55005004992).
Almost surely, 2110010009983 is an apocalyptic number.
110010009983 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010009983 is an equidigital number, since it uses as much as digits as its factorization.
110010009983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 32.
Adding to 110010009983 its reverse (389900010011), we get a palindrome (499910019994).
The spelling of 110010009983 in words is "one hundred ten billion, ten million, nine thousand, nine hundred eighty-three".
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