11001009983 has 2 divisors, whose sum is σ = 11001009984. Its totient is φ = 11001009982.

The previous prime is 11001009979. The next prime is 11001010003. The reversal of 11001009983 is 38990010011.

It is a weak prime.

It is an emirp because it is prime and its reverse (38990010011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001009983 - 2² = 11001009979 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001009913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500504991 + 5500504992.

It is an arithmetic number, because the mean of its divisors is an integer number (5500504992).

Almost surely, 2^11001009983 is an apocalyptic number.

11001009983 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001009983 is an equidigital number, since it uses as much as digits as its factorization.

11001009983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 32.

Adding to 11001009983 its reverse (38990010011), we get a palindrome (49991019994).

The spelling of 11001009983 in words is "eleven billion, one million, nine thousand, nine hundred eighty-three".