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110010109998053 is a prime number
BaseRepresentation
bin11001000000110110111001…
…100001110011001111100101
3112102111212022201021220012102
4121000312321201303033211
5103404401201124414203
61025545540304101445
732112653036214536
oct3100667141631745
9472455281256172
10110010109998053
1132064031155391
1210408843304885
13494cba79c3125
141d2473693868d
15cab93709c888
hex640db98733e5

110010109998053 has 2 divisors, whose sum is σ = 110010109998054. Its totient is φ = 110010109998052.

The previous prime is 110010109997987. The next prime is 110010109998083. The reversal of 110010109998053 is 350899901010011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62586737347684 + 47423372650369 = 7911178^2 + 6886463^2 .

It is a cyclic number.

It is not a de Polignac number, because 110010109998053 - 218 = 110010109735909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110010109997989 and 110010109998007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110010109998083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005054999026 + 55005054999027.

It is an arithmetic number, because the mean of its divisors is an integer number (55005054999027).

Almost surely, 2110010109998053 is an apocalyptic number.

It is an amenable number.

110010109998053 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010109998053 is an equidigital number, since it uses as much as digits as its factorization.

110010109998053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 87480, while the sum is 47.

The spelling of 110010109998053 in words is "one hundred ten trillion, ten billion, one hundred nine million, nine hundred ninety-eight thousand, fifty-three".